Vintage Karting Forum

This is probably the last piece I need to finish my Mc10 clone.

Only came on Mc10 and D44 saw.

McCulloch P/n = 51228

Pm or email me if you have one to sell.
Damaged is OK, I can probable fix most any damage.

Scott

I am all set, Cat Kart stepped up on a tip from Stroker Ace.
Thank you for all the input,
Scott

Also the model 55.

(04-01-2020, 04:43 PM)Scott Kneisel Wrote: [ -> ]This is probably the last piece I need to finish my Mc10 clone.

Only came on Mc10 and D44 saw.

McCulloch P/n = 51228

Pm or email me if you have one to sell.
Damaged is OK, I can probable fix most any damage.

Scott

HELLO SCOTT
.
Try this 
.
.

https://www.ebay.com/itm/FLYWHEEL-SHROUD...Sw-rReTfBP

That shroud on ebay fits Super 44/55 and newer models. Doesnt come quite close to the D44/55.


BUT...........



If you like welding this magnesium its not too difficult to cut the top edge down on later model shroud and convert to a D44 style. I have done them in the past, but it is a little time consuming. Patience is required.



This area can even be notched out to resemble the earlier shroud. It is an option.

(04-02-2020, 03:26 PM)Terry Bentley Wrote: [ -> ]That shroud fits Super 44/55 and newer models. Doesnt come quite close to the D44/55.


BUT...........



If you like welding this magnesium its not too difficult to cut the top edge down on later model shroud and convert to a D44 style. I have done them in the past, but it is a little time consuming. Patience is required.



This area can even be notched out to resemble the earlier shroud. It is an option.

---

Scott is correct!  Only on the D44 and Mc-10.  The same is true for the cylinder head.

These are the two chainsaw models with correct head and shroud.





The D44 is a direct drive model using .404 chain.



The model 55 powerhead is identical but has a governor with gear reduction transmission and uses 1/2" chain.

Got it
will keep looking

I believe there is one on ebay now, but he saw you coming.

Got one from Tim Hinson at Cat Kart,
Thanks for all the input.
Scott